Question

An $AC$ circuit has $R=100\Omega ,C=2\mu F$ and $L=80\text{mH}$ connected in series. The quality factor of the circuit is :

• A. $2$
• B. $0.5$
• C. $20$
• D. $400$

Answer 1

The correct option is A $2$

Quality factor is given by,
$Q=\frac{1}{R}\sqrt{\frac{L}{C}}=\frac{1}{100}\sqrt{\frac{80\times {10}^{-3}}{2\times {10}^{-6}}}$
$=\frac{1}{100}\sqrt{40\times {10}^3}=\frac{200}{100}=2$