An AC consumes 8 units of electricity in 30 minutes and a bulb consumes 18 units of electricity in 6 hours. How many total units of electricity will both the AC and the bulb consume in 8 days, if they run 10 hours a day?

1250 units

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1528 units

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1248 units

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1520 units

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1620 units

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Solution

The correct option is D 1520 units
Here, total electric consumption
$= (10 \times 16 \times 8) + (3 \times 10 \times 8) u n i t s$
$= (1280 + 240) = 1520 u n i t s$

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An AC consumes 8 units of electricity in 30 minutes and a bulb consumes 18 units of electricity in 6 hours. How many total units of electricity will both the AC and the bulb consume in 8 days, if they run 10 hours a day?

The correct option is D 1520 unitsHere, total electric consumption =(10×16×8)+(3×10×8)units =(1280+240)=1520 units

The correct option is D 1520 units
Here, total electric consumption
$= (10 \times 16 \times 8) + (3 \times 10 \times 8) u n i t s$
$= (1280 + 240) = 1520 u n i t s$