An AC rms voltage of 2 V having a frequeney of 50 KH is applied to a condenser of capacity of 10 - F The maximum value of the magnetic field between the plates of the condenser if the radius of plate is 10 cm is

The magnetic field due to a current carrying circular loop of radius 3 cm at a point on its axis at a distance of 4 cm from the centre is 54 $μ$ T. The magnetic field (in $μ$ T) at the centre of the loop will be

Q. A parallel plate condenser of capacity

10 μ F

is connected to an A.C. supply voltage

e = 4 sin (100 π t)

. The maximum displacement current:

Q. Two parallel long wires carry currents

i_{1}

and

i_{2}

with

i_{1} > i_{2}

. when the currents are in the same direction, the magnetic field at a point midway between the wires is

10 μ T

. If the direction of

i_{2}

is reversed, the field becomes

30 μ T

. The ratio

\frac{i_{1}}{i_{2}}

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An AC rms voltage of 2V having a frequeney of 50KH is applied to a condenser of capacity of 10 μF The maximum value of the magnetic field between the plates of the condenser if the radius of plate is 10cm is

The correct option is B 2μTGiven: Radius of the plate= 10 cm Frequency=50 kHz Voltage= 2V Capacitor= 10μFSolution: As we know,B=μI2πr (1)But, I=CVfwhere, f is the frequencysubstituting the value of current in equation (1) we get,B=μCVf2πr putting the values we get,B=2μT

An AC rms voltage of 2 $V$ having a frequeney of 50 $K H$ is applied to a condenser of capacity of 10 $μ F$ The maximum value of the magnetic field between the plates of the condenser if the radius of plate is 10 $c m$ is