Question

An $AC$ source is connected to a capacitor. What will happen to the rms current if a dielectric slab is inserted into the capacitor.

• A. Increase
• B. Decrease
• C. Remains same
• D. Cannot be determined

Answer 1

The correct option is A Increase

We know that the rms current is given by :

$i_{rms}=\frac{E_{\text{peak}}}{\sqrt{2}{X}_C}$

Here, $X_C=\frac{1}{\omega C}$

When a dielectric slab is inserted into the capacitor, the capacitance of the capacitor will increase. Therefore, the value of $X_C$ will decrease.

As, $i_{rms}\propto \frac{1}{X_C}$

$\therefore i_{rms}$ will increase.

Hence, $\left(A\right)$ is the correct answer.