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Question

An AC source rated 100 V (rms) supplies a current of 10 A (rms) to a circuit. The average power delivered by the source

A
Must be 1000 W
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B
May be 1000 W
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C
May be greater than 1000 W
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D
May be less than 1000 W
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Solution

The correct options are
B May be 1000 W
D May be less than 1000 W
We know that average power is given by
Pavg=VrmsIrmscos ϕ
Given that
Vrms=100 V and
Irms=10 A

Now we know cosϕ ranges from 1 to 1
But considering only the magnitude we can say
maximum value of cosϕ=1
minimum value of cosϕ=0
So it can have average power upto 1000 W
So only option (b) and (d) are correct

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