An AC source rated 100V (rms) supplies a current of 10A (rms) to a circuit. The average power delivered by the source
A
Must be 1000W
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B
May be 1000W
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C
May be greater than 1000 W
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D
May be less than 1000 W
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Solution
The correct option is D May be less than 1000 W We know that average power is given by Pavg=VrmsIrmscosϕ
Given that Vrms=100V and Irms=10A
Now we know cosϕ ranges from −1to1
But considering only the magnitude we can say
maximum value of cosϕ=1
minimum value of cosϕ=0
So it can have average power upto 1000W
So only option (b) and (d) are correct