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Question

An AC source rated 100 V (rms) supplies a current of 10 A (rms) to a circuit. The average power delivered by the source

(a) must be 1000 W
(b) may be 1000 W
(c) may be greater than 1000 W
(d) may be less than 1000 W

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Solution

(b) may be 1000 W
(d) may be less than 1000 W

The average power delivered by an AC source is given by,
Pavg=VrmsIrmscosϕ
Given:
Vrms = 100 V
Irms = 10 A
Pavg=1000cosϕ
ϕ-π2,π2
cosϕ0,1
0Pavg1000

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