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Question

An AC voltage E=220sin(ωtπ6) is connected across a certain device. The current flowing through this device is i=115 sin(ωt+π3). The correct phasor diagram, of applied voltage and current flowing in the circuit, is,

A
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C
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Solution

The correct option is C
Given:
E=220sin(ωtπ6)

i=115sin(ωt+π3)

From the equations of current and voltage, we can say that the current is leading the voltage.

The phase difference between the current and voltage is,

ϕ=π3(π6)=π2

Also, the magnitude of voltage is more than the magnitude of current.

Hence, the phasor diagram can be drawn as follows,


Hence, (C) is the correct answer.

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