An achromatic prism is made by combination of two prism P1 -F - 1-523- -C - 1-515 and P2 -F - 1-616- -C - 1-650- If the angle of prism P1 is 10o then the angle of prism P2 will be -

The correct option is A 2.35^o For deviation without dispersions #160; #160;(Achromatic combination) A_2/A_1 = μ_1 v μ_1 R/μ_2v μ_2R = ...

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Standard X

Physics

Minimum Deviation

An achromatic...

Question

An achromatic prism is made by combination of two prism $P_{1} (μ_{F} = 1.523, μ_{C} = 1.515)$ and $P_{2} (μ_{F} = 1.616, μ_{C} = 1.650)$ . If the angle of prism $P_{1}$ is $10^{o}$ then the angle of prism $P_{2}$ will be ________.

{2.35}^{o}

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{10.6}^{o}

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{7.8}^{o}

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5^{o}

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Solution

The correct option is A ${2.35}^{o}$
For deviation without dispersions (Achromatic combination)
$\frac{A_{2}}{A_{1}} = - \frac{μ_{1} v - μ_{1 R}}{μ_{2 v} - μ_{2 R}}$
$= \frac{1.523 - 1.515}{1.616 - 1.650} = \frac{0.008}{0.034} = 0.2353$
$A_{2} = 10^{o} \times (0.2353) = 2^{o} 21^{'} 11 "\approx {2.35}^{o}$

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An achromatic prism is made by combination of two prism P1(μF=1.523,μC=1.515) and P2(μF=1.616,μC=1.650). If the angle of prism P1 is 10o then the angle of prism P2 will be ________.

The correct option is A 2.35oFor deviation without dispersions (Achromatic combination)A2A1=−μ1v−μ1Rμ2v−μ2R=1.523−1.5151.616−1.650=0.0080.034=0.2353A2=10o×(0.2353)=2o21′11"≈2.35o

An achromatic prism is made by combination of two prism $P_{1} (μ_{F} = 1.523, μ_{C} = 1.515)$ and $P_{2} (μ_{F} = 1.616, μ_{C} = 1.650)$ . If the angle of prism $P_{1}$ is $10^{o}$ then the angle of prism $P_{2}$ will be ________.