An acid is added to water to make 30 mL of a solution with a pH of 6.5. If he solution is then diluted to a total volume of 300 mL, what will be the new value of pH?

6.5

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Between 6.5 and 7

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7.5 because the hydrogen ion concentration is reduced by a factor of 10.

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Either A or B depending upon what acid was used, but C is impossible.

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Solution

The correct option is B Between 6.5 and 7
The $p H$ of $300 m l$ solution is between $6.5$ and $7$ .

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20

3

100

H^{+}

\frac{N}{10}

H C l

N a_{2} C O_{3}

\frac{N}{50}

The hydrogen ion concentration of a solution prepared by diluting 50 mL of 0.10M $H N O_{3} (a q)$ with water to make it up to 500 mL is:

0.1 M H C O O N a

50 mL

0.05 M

p H = 4.0

p K_{a}

= 3.7

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