An acid solution with pH = 6 at $25^{0}$ C is diluted by $10^{2}$ times. The pH of solution will ?

Decrease by 0.95 approximately

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Increase by 0.95 approximately

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decrease by 2

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Increase by 2

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Solution

The correct option is A Increase by 0.95 approximately
Given concentration of $H^{+}$ $i o n i s$ 10^{-6} $a n d o n d i l u t i o n t o 100 t i m e s i t b e c o m e s$ 10^{-8}$

total concentration $H^{+} = 1 \times 10^{- 7} + 1 \times 10^{- 8}$ $= 1.1 \times 10^{- 7}$ M
pH = 6.95
So pH increases by the 0.95

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