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Standard X

Chemistry

Factors Affecting Electrolysis

An acidic sol...

Question

An acidic solution of $C u^{2 +}$ containing $0.4$ g of $C u^{2 +}$ ions is electrolysed until all the copper is deposited. The volume of oxygen evolved at NTP is:

141 c c

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31.75 c c

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64 c c

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32 c c

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Solution

The correct option is B $141 c c$
Moles of $C u = \frac{0.4}{63.5} = 6.3 \times 10^{- 3}$ $m o l$
Faraday used $= 2 \times 6.3 \times 10^{- 3} = 12.6 \times 10^{- 3}$ $m o l$
Now for oxygen,
$2 H_{2} O ⟶ O_{2} + 4 H^{+} + 4 e^{-}$
Hence, $4$ $m o l$ $e^{-} ⟶ 22400$ $c m^{3}$ of $O_{2}$ .
$12.6 \times 10^{- 3} ⟶ \frac{22400}{2} \times 12.6 \times 10^{- 3}$ $c m^{3}$ of $O_{2}$
$= 141$ $c m^{3}$

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An acidic solution of Cu2+ containing 0.4g of Cu2+ ions is electrolysed until all the copper is deposited. The volume of oxygen evolved at NTP is:

The correct option is B 141ccMoles of Cu=0.463.5=6.3×10−3 molFaraday used =2×6.3×10−3=12.6×10−3 molNow for oxygen,2H2O⟶O2+4H++4e−Hence, 4 mol e−⟶22400 cm3 of O2.12.6×10−3⟶224002×12.6×10−3 cm3 of O2=141 cm3

An acidic solution of $C u^{2 +}$ containing $0.4$ g of $C u^{2 +}$ ions is electrolysed until all the copper is deposited. The volume of oxygen evolved at NTP is: