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Question

An acidic solution of Cu2+ salt containing 0.4 g of Cu2+ is electrolysed until all the copper is deposited. The electrolysis is continued for seven more minutes will volume of solution kept at 100 mL and the current at 1.2 amp. Calculate the gases evolved at NTP during the entire electrolysis.

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Solution

0.4 g of Cu2+=0.431.75=0.0126 g equivalent
At the same time, the oxygen deposited at anode
0.0126 gequivalent
=832×0.0126=0.00315 gmole
After the complete deposition of copper, the electrolysis will discharge hydrogen at cathode and oxygen at anode.
The amount of charge passed =1.2×7×60=504 coulomb
So, Oxygen liberated =196500×504=0.00523 gequivalent
=832×0.00523=0.001307 gmole
Hydrogen liberated =0.00523 gequivalent
=12×0.00523=0.00261 gmole
Total gases evolve =(0.00315+0.001307+0.00261)gmole
=0.007067 gmole
Volume of gases evolved at NTP
=22400×0.007967 mL
=158.3 mL.

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