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Question

An adiabatic expansion of an idea gas always has:

A
decrease in temperature
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B
q=O
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C
w=O
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D
H=O
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Solution

The correct option is B q=O
Adiabatic free expansion of a gas. ... For an ideal gas, the temperature remains constant because the internal energy only depends on temperature in that case. Since at constant temperature, the entropy is proportional to the volume, the entropy increases in this case, therefore this process is irreversible.

Q = 0

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