An adult weighing $600 N$ raises the centre of gravity of his body by $0.25 m$ while taking each step of $1 m$ length in jogging. If he jogs of $6 k m$ , the energy utilised by him in jogging is:

9 \times 10^{6} J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9 \times 10^{5} J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6 \times 10^{6} J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 \times 10^{5} J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $9 \times 10^{5} J$
Here, $m g = 600 N, h = 0.25 m$
Length of each step $= 1 m$
$∴$ No of steps in $6 k m$ is $N = \frac{6 \times 10^{3} m}{1 m} = 6000$
$∴$ Energy utilised in jogging is
$E = N m g h$
$= 6000 \times 600 N \times 0.25 m$
$= 9 \times 10^{5} J$ .

Suggest Corrections

Similar questions

Q. Mary jogs

9

km at a speed of

6

km per hour. At what speed would she need to jog during the next

1.5

hours to have an average of

9

km per hour for the entire jogging session?

Each morning, John jogs at 6 miles per hour and rides a bike at 12 miles per hour. His goal is to jog and ride his bike a total of at least 9 miles in less than 1 hour. If John jogs j miles and rides his bike b miles, which of the following systems of inequalities represents John’s goal?

Q. Mohit who is overweight is advised by his doctor to go for a morning jog to reduce weight. He goes to a park which is in the shape of a rectangle of length

80 m

and width

40 m

. If he jogs five rounds of the park daily, how much distance is covered by him in kilometers?

The latent heat of vaporisation of water is:
(a) $2.25 \times 10^{6} J / K g$ (a) $3.34 \times 10^{6} J / K g$
(c) $2.25 \times 10^{4} J / K g$ (d) $33.4 \times 10^{5} J / K g$

There is a park with two triangular jogging tracks. Rahul and his friend Arjun went for jogging. The park had a route map which mentioned that the sides of jogging tracks with the same color have the same length and nothing was mentioned about different colored sides.

Both of them started jogging at 7 AM on different tracks. Rahul finished his jogging at 7:40 AM. At what time will Arjun finish his jogging if both of them are jogging at the same speed,given that the triangular tracks are congruent to each other?

Join BYJU'S Learning Program

An adult weighing 600 N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jogs of 6 km, the energy utilised by him in jogging is:

The correct option is B 9×105JHere, mg=600 N,h=0.25 mLength of each step =1 m∴ No of steps in 6 km is N=6×103m1 m=6000∴ Energy utilised in jogging isE=Nmgh=6000×600 N×0.25 m=9×105J.

An adult weighing $600 N$ raises the centre of gravity of his body by $0.25 m$ while taking each step of $1 m$ length in jogging. If he jogs of $6 k m$ , the energy utilised by him in jogging is:

The correct option is B $9 \times 10^{5} J$
Here, $m g = 600 N, h = 0.25 m$
Length of each step $= 1 m$
$∴$ No of steps in $6 k m$ is $N = \frac{6 \times 10^{3} m}{1 m} = 6000$
$∴$ Energy utilised in jogging is
$E = N m g h$
$= 6000 \times 600 N \times 0.25 m$
$= 9 \times 10^{5} J$ .