CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

An aeroplane at an altitude of 1500 metres finds that two ships are sailing towards it in the same direction. The angles of depression as observed from the aeroplane are 45 and 30 respectively. Find thee distance (in m) between the two ships

Open in App
Solution

Let D is the aeroplane A and B are two ships.
Given: CD=1500 m,EDA=30,EDB=45
In $\triangle DBC\ ,
tan45=DCBC
=1500BC
1=1500BC
BC=1500 m
In ADC,
tan30=DCAC
13=1500AB+BC
AB+BC=15003
AB=150031500
AB=1500(31)
=1500(1.731)=1500×0.73
=1095 m.
Hence, distance between two ships =1095 m.

615554_578744_ans_63adcea692344d9da152f1fe8f021de2.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Questions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon