An aeroplane covered a distance of $400 k m$ at an average speed of $x k m / h$ . on the return journey, the speed was increased by $40 k m / h$ . Write down an expression for the time taken for : (i) the onward journey . (ii) the return journey

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Solution

Total distance $= 400$ km

Average speed for energy $=$ r km/hr

(i) Time taken for covered journey $= \frac{d i s t a n c e}{s p e e d}$

$= \frac{400}{x}$ hr

(ii) Time taken for return journey $= \frac{d i s t a n c e}{s p e e d}$

$= \frac{400}{x + 40}$ hr

( $∵$ The total speed was increased by $40$ ).

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An aeroplane covered a distance of 400 km at an average speed of x km/h. on the return journey, the speed was increased by 40 km/h. Write down an expression for the time taken for : (i) the onward journey . (ii) the return journey

Total distance =400kmAverage speed for energy=r km/hr(i) Time taken for covered journey=distancespeed=400xhr(ii) Time taken for return journey=distancespeed=400x+40hr(∵ The total speed was increased by 40).

An aeroplane covered a distance of $400 k m$ at an average speed of $x k m / h$ . on the return journey, the speed was increased by $40 k m / h$ . Write down an expression for the time taken for : (i) the onward journey . (ii) the return journey