An aeroplane flying 490 m above ground level at 100 m/s, releases a block. What horizontal distance would it travel before it hits the ground?

0.1 km

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1 km

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2 km

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0.5 km

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Solution

The correct option is B
1 km

S = u $\times$ $\sqrt{\frac{2 h}{g}}$ =100 $\times$ $\sqrt{\frac{2 \times 490}{9.8}}$ =1000m=1km.

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Similar questions

An aeroplane flying 490 m above ground level at 100 m/s, releases a block. How far on ground will it strike

490 m

100 m/s

g = 9.8 {m/s}^{2}

490 m

100 m/s

g = 9.8 {m/s}^{2}

490

100

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