An aeroplane has to go from a point A to B due north. Wind is blowing due east at a speed of 250km/h. If the air speed of plane is 500km/h then its direction of head to reach point B is :
A
15∘ west of north
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B
60∘ west of north
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C
45∘ west of north
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D
30∘ west of north
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Solution
The correct option is D30∘ west of north Let us suppose aeroplane heads at an angle of θ west of north.
The data given in the question is shown in the figure below.
To reach from point A to B, velocity (vn) of aeroplane should be along the direction of AB. ∴ velocity along the West-East axis should be equal to zero. ⇒∑vw−e=0 ⇒250−500sinθ=0 sinθ=12 ⇒θ=30∘
The aeroplane should head at an angle of 30∘ west of north.
Hence, option (d) is correct answer.