An aeroplane in which the distance between the tips of the wings is 50m is flying horizontally with speed of 360 km/h over a place where the vertical component of earth’s magnetic field is $2 \times 10^{4}$ The potential difference between the tips of the wings would be

0.1V

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1 V

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0.2V

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0.01V

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Solution

The correct option is B 1 V
$E = B l v$
$= 2 \times 10^{- 4} \times 50 \times 360 \times \frac{5}{18} V$
$= 1 V$

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An aeroplane in which the distance between the tips of the wings is 50m is flying horizontally with speed of 360 km/h over a place where the vertical component of earth’s magnetic field is 2×104 The potential difference between the tips of the wings would be

The correct option is B 1 VE=Blv =2×10−4×50×360×518 V = 1V

An aeroplane in which the distance between the tips of the wings is 50m is flying horizontally with speed of 360 km/h over a place where the vertical component of earth’s magnetic field is $2 \times 10^{4}$ The potential difference between the tips of the wings would be

The correct option is B 1 V
$E = B l v$
$= 2 \times 10^{- 4} \times 50 \times 360 \times \frac{5}{18} V$
$= 1 V$