Question

An aeroplane is flying horizontally with a velocity of $360$ km/h. The distance between the tips of the wings of aeroplane is $25m$. The vertical component of earth's magnetic field is $4\times {10}^{-4}Wb/m^2$. The induced e.m.f. is

• A. $1$ V
• B. $100$ V
• C. $1$ kV
• D. Zero

Answer 1

The correct option is A $1$ V

Given,

$B=4\times {10}^{-4}Wb/m^2$

$v=360km/h=\frac{360\times 1000}{60\times 60}=100m/s$

$l=25m$

The induced emf can be given by the expression:

$emf=Blv$

$\Rightarrow emf=4\times {10}^{-4}\times 25\times 100=1V$

The correct option is $A$.