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Standard XII

Physics

Applications of Horizontal and Vertical Components

An aeroplane ...

Question

An aeroplane is in a level flight at $144 k m / h r$ at an altitude of $1000 m$ . How far from a given target a bomb be released from it to hit the target ?(take $g = 10 m / s^{2}$ )

566 m

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671.43 m

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471.34 m

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371.34 m

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Solution

The correct option is A $566 m$
as time to fall
$S = \frac{1}{2} \times g \times t^{2}$
$\frac{100 \times 2}{10} = t^{2}$
$t = \sqrt{200} = 10 \sqrt{2}$
$= 14.14 s$
so Speed = $144 \times \frac{1000}{3600} = 40$
so, $x = 40 \times t = 40 \times 14.14$
$= 565.6 m$

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[g = 10 {m/s}^{2}]

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An aeroplane is in a level flight at 144km/hr at an altitude of 1000m. How far from a given target a bomb be released from it to hit the target ?(take g=10m/s2)

The correct option is A 566mas time to fallS=12×g×t2100×210=t2t=√200=10√2=14.14sso Speed =144×10003600=40so,x=40×t=40×14.14=565.6m

An aeroplane is in a level flight at $144 k m / h r$ at an altitude of $1000 m$ . How far from a given target a bomb be released from it to hit the target ?(take $g = 10 m / s^{2}$ )

The correct option is A $566 m$
as time to fall
$S = \frac{1}{2} \times g \times t^{2}$
$\frac{100 \times 2}{10} = t^{2}$
$t = \sqrt{200} = 10 \sqrt{2}$
$= 14.14 s$
so Speed = $144 \times \frac{1000}{3600} = 40$
so, $x = 40 \times t = 40 \times 14.14$
$= 565.6 m$