An aeroplane is moving towards north horizontally with a speed of 200 m-s at a place where the vertical component of earths magnetic field is 0-5- 10 -4 tesla- Then the induced e-m-f- set up between the tips of the wings of the plane if they are 10 m apart is-

The correct option is B 0.1 volt EMF=Blv =.5× 10 ^ 4 × 10× 200 =0.1V ...

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Byju's Answer

Standard XII

Physics

Motional EMF

An aeroplane ...

Question

An aeroplane is moving towards north horizontally with a speed of $200 m / s$ at a place where the vertical component of earths magnetic field is $0.5 \times 10^{- 4}$ tesla. Then the induced e.m.f. set up between the tips of the wings of the plane if they are $10 m$ apart is:

0.1 volt

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Solution

The correct option is B 0.1 volt
$E M F = B l v$
$= .5 \times 10^{- 4} \times 10 \times 200$
$= 0.1 V$

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An aeroplane is moving towards north horizontally with a speed of 200m/s at a place where the vertical component of earths magnetic field is 0.5×10−4 tesla. Then the induced e.m.f. set up between the tips of the wings of the plane if they are 10m apart is:

The correct option is B 0.1 voltEMF=Blv=.5×10−4×10×200=0.1V

An aeroplane is moving towards north horizontally with a speed of $200 m / s$ at a place where the vertical component of earths magnetic field is $0.5 \times 10^{- 4}$ tesla. Then the induced e.m.f. set up between the tips of the wings of the plane if they are $10 m$ apart is:

The correct option is B 0.1 volt
$E M F = B l v$
$= .5 \times 10^{- 4} \times 10 \times 200$
$= 0.1 V$