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Question

An aeroplane is passing through an air tunnel. The velocity of air is 70 m/s and 63 m/s respectively at its upper surface of wing and lower surface of wing. Find out the lifting force. Given that total wing area is 2.5 m2 and air density is 1.3 kg/m3.

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Solution

Given v2=70 ms1;v1=63 ms1;
p=1.3 kgm3,F=? A=2.5 m2

From Bernoulli's theorem

P1+12pv21=P2+12pv22

P1P2=12pv2212pv21=12p(v22v21)

or ΔP=12×1.3(v2+v2)(v2v2)

=1.32(70+63)(7063)

=1.32×133×7

or ΔP=605.15 Nm2

Lifting force F=ΔPA=605.15×2.5=11512.875
or F=1.5×103 N

1755269_1835126_ans_e59aed2929b54cb986b08fd00da7a817.png

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