Derivation of Position-Time Relation by Graphical Method
An aeroplane ...
Question
An aeroplane leaves an airport and flies due north at a speed of 1,000km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1,200km per hour. How far apart will be the two planes after 112 hours?
A
300√51km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
300√61km
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
350√61km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2100km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B300√61km
Speed of first aeroplane = 1000 km/hr Distance covered by first aeroplane due north in 112hours(OA)=100×32km=1500km Speed of second aeroplane = 1200 km/hr Distance covered by second aeroplane due west in112hours(OB)=1200×32km=1800km In right angle ΔAOB, we have AB2=AO2+OB2 ⇒AB2=(1500)2+(1800)2 ⇒AB=√2250000+3240000 =√5490000 ⇒AB=300√61km Hence, the distance between two aeroplanes will be 300√61km.