Question

An aeroplane moves $400\text{m}$ towards north, $300\text{m}$ towards west and then $1200\text{m}$ vertically upward, then its displacement from the initial position is

• A. $1600\text{m}$
• B. $1800\text{m}$
• C. $1500\text{m}$
• D. $1300\text{m}$

Answer 1

The correct option is D $1300\text{m}$


Here $CD$ is perependicular to the palne of paper. Required distance $=BD$
$B{D}^2=C{B}^2+C{D}^2={500}^2+{1200}^2$
$BD=\sqrt{{500}^2+{1200}^2}=1300\text{m}$