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Question

# An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a height of 396.9 m. The time taken by a food packet to reach the ground and its horizontal range is (Take g=9.8 m/sec2).

A
3sec and 2000m
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B
5sec and 500m
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C
8sec and 1500m
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D
9sec and 1800m
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Solution

## The correct option is D 9sec and 1800mWe know thatAs the packet simply gets dropped, it's initial vertical velocity u = 0Time taken for the packet to reach ground isT =√(2H/g) = √(2*396.9/9.8) = √81 = 9sHorizontally the packet travels at the speed of aeroplane,V = 720kmph = 720*(5/18) = 200m/sRange R = V*T = 200*9 = 1800m

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