The correct option is A 300kmhr
Let the usual speed of the plane be x kmhr.
As per the question.
[1200x]−[1200(x+100)]=1
⇒1200(x+100)−1200x=x(x+100)
⇒120000=x2+100x
⇒x2+100x−120000=0
⇒x2+400x−300x−120000−0
⇒(x+400)(x−300)=0
Thus, x = - 400 or 300.
But speed can't be negative.
⇒x=300.
Thus, the usual speed of the place is 300 kmhr.