An aeroplane takes off at an angle of 30∘ to the horizontal. If the component of its velocity along the horizontal is 200√3km/h. What is its actual velocity? Also find the vertical component of velocity.
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Solution
As per question, V0cos30∘=200√3kmph V0√32=200√3kmph ∴V0=400kmph Vertical component =V0sin30∘=400×12=200kmph