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Question

An aeroplane takes off at an angle of 60o to the horizontal. If the velocity of the plane is 200kmh1, calculate its horizontal and vertical component of its velocity.

A
νysinθ=3003kmh1
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B
νysinθ=1003kmh1
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C
νysinθ=2003kmh1
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D
νysinθ=4003kmh1
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Solution

The correct option is A νysinθ=1003kmh1
Here ν=200kmh1
θ=60o
Horizontal component
νx=νcosθ=200cos60o
=200×12=100kmh1
Vertical component
νysinθ=200sin60o=200×32=1003kmh1

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