An aeroplane with wing span $50 m$ is flying horizontally with a speed of $360 k m / h r$ over a place where the vertical component of the earth's magnetic field is $2 \times 10^{- 4} W b / m^{2}$ . The potential difference between the tips of the wings would be

0.1 V

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1.0 V

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0.2 V

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0.01 V

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Solution

The correct option is B $1.0 V$
$I n d u c e d e m f E = B r v l$
Velocity of plane= $\frac{360 \times 1000}{3600} = 100 m / s$
$⟹ 2 \times 10^{- 4} \times 100 \times 50$
$= 1 V$

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An aeroplane in which the distance between the tips of wings is 50 m is flying horizontally with a speed of 360 km/hr over a place where the vertical component of earth's magnetic field is $2.0$ x $10^{- 4} w e b e r / m^{2}$ . The potential difference between the tips of the wings would be

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An aeroplane with wing span 50 m is flying horizontally with a speed of 360 km/hr over a place where the vertical component of the earth's magnetic field is 2×10−4Wb/m2. The potential difference between the tips of the wings would be

The correct option is B 1.0VInducedemfE=BrvlVelocity of plane=360×10003600=100m/s⟹2×10−4×100×50=1V

An aeroplane with wing span $50 m$ is flying horizontally with a speed of $360 k m / h r$ over a place where the vertical component of the earth's magnetic field is $2 \times 10^{- 4} W b / m^{2}$ . The potential difference between the tips of the wings would be

The correct option is B $1.0 V$
$I n d u c e d e m f E = B r v l$
Velocity of plane= $\frac{360 \times 1000}{3600} = 100 m / s$
$⟹ 2 \times 10^{- 4} \times 100 \times 50$
$= 1 V$