An air bubble in a glass slab( $μ = 1.5$ ) is $6$ cm deep as viewed from one face and $4$ cm deep as viewed from the other face. The thickness of the slab is:

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Solution

Let us take $d_{1} = 6 c m$ and $d_{2} = 4 c m$ and $μ = 1.5$

Now. Actual width is the sum of real depth from the 2 sides $= d_{1} \times x + d_{2} \times x = 4 \times 1.5 + 6 \times 1.5$
$= 15 c m$

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An air bubble in a glass slab(μ=1.5) is 6cm deep as viewed from one face and 4 cm deep as viewed from the other face. The thickness of the slab is:

Let us take d1=6cm and d2=4cm and μ=1.5Now. Actual width is the sum of real depth from the 2 sides =d1×x+d2×x=4×1.5+6×1.5=15cm

An air bubble in a glass slab( $μ = 1.5$ ) is $6$ cm deep as viewed from one face and $4$ cm deep as viewed from the other face. The thickness of the slab is:

Let us take $d_{1} = 6 c m$ and $d_{2} = 4 c m$ and $μ = 1.5$

Now. Actual width is the sum of real depth from the 2 sides $= d_{1} \times x + d_{2} \times x = 4 \times 1.5 + 6 \times 1.5$
$= 15 c m$