An air bubble in a glass with refractive index $1.5$ (near normal incidence) i.e. $5 c m$ deep when viewed from one surface and $3 c m$ deep when viewed from the opposite face. The thickness(in $c m$ ) of the is.

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Solution

The correct option is A $12$
The apparent dept of bubble as seen from one surface= $\frac{d_{1}}{μ} = 5 c m$

$⟹$ Real depth of bubble from one surface $d_{1} = 7.5 c m$

Similarly real depth of bubble from other surface= $d_{2} = 1.5 \times 3 c m = 4.5 c m$

Hence the thickness of the glass is $d_{1} + d_{2} = 12 c m$

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An air bubble in a glass with refractive index 1.5 (near normal incidence) i.e. 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness(in cm) of the is.

The correct option is A 12The apparent dept of bubble as seen from one surface=d1μ=5cm⟹ Real depth of bubble from one surface d1=7.5cmSimilarly real depth of bubble from other surface=d2=1.5×3cm=4.5cmHence the thickness of the glass is d1+d2=12cm

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