An air bubble in glass slab $(μ = 1.5)$ when viewed from one side appears to be at 6 $c m$ and from opposite side 4 $c m .$ The thickness of glass slab is :

10 c m

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6.67 c m

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15 c m

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Solution

The correct option is B $15 c m$
Given $μ = 1.5$
Apparent depths, $d1=6cm \& d2=4cm$
$D = μ d$
$∴ D_{1} = 1.5 \times 6 = 9.0 c m$
$∴ D_{2} = 1.5 \times 4 = 6.0 c m$
Hence, thickness of glass slab $= 9.0 + 6.0 = 15.0 c m$
Therefore the correct answer is option (C).

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An air bubble in glass slab (μ=1.5) when viewed from one side appears to be at 6cm and from opposite side 4cm. The thickness of glass slab is :

The correct option is B 15cmGiven μ=1.5Apparent depths, d1=6cm \& d2=4cmD=μd∴D1=1.5×6=9.0cm∴D2=1.5×4=6.0cmHence, thickness of glass slab=9.0+6.0=15.0cmTherefore the correct answer is option (C).

An air bubble in glass slab $(μ = 1.5)$ when viewed from one side appears to be at 6 $c m$ and from opposite side 4 $c m .$ The thickness of glass slab is :

The correct option is B $15 c m$
Given $μ = 1.5$
Apparent depths, $d1=6cm \& d2=4cm$
$D = μ d$
$∴ D_{1} = 1.5 \times 6 = 9.0 c m$
$∴ D_{2} = 1.5 \times 4 = 6.0 c m$
Hence, thickness of glass slab $= 9.0 + 6.0 = 15.0 c m$
Therefore the correct answer is option (C).