An air bubble in sphere having $4$ cm diameter appears $1$ cm from surface nearest to eye when loaded along diameter. If $_{a} μ_{g} = 1.5$ , the distance of bubble from refracting surface is?

1.2

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Solution

The correct option is A $1.2$ cm
$v = 1 c m$

$R = 2 c m$

$B y u s i n g \frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$

$\frac{1}{- 1} - \frac{1.5}{μ} = \frac{1 - 1.5}{- 2} = 1.2 c m$

$μ = 1.2 c m$

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An air bubble in sphere having 4 cm diameter appears 1cm from surface nearest to eye when loaded along diameter. If aμg=1.5, the distance of bubble from refracting surface is?

The correct option is A 1.2cmv=1cmR=2cmByusingμ2v−μ1u=μ2−μ1R1−1−1.5μ=1−1.5−2=1.2cmμ=1.2cm

An air bubble in sphere having $4$ cm diameter appears $1$ cm from surface nearest to eye when loaded along diameter. If $_{a} μ_{g} = 1.5$ , the distance of bubble from refracting surface is?

The correct option is A $1.2$ cm
$v = 1 c m$

$R = 2 c m$

$B y u s i n g \frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$

$\frac{1}{- 1} - \frac{1.5}{μ} = \frac{1 - 1.5}{- 2} = 1.2 c m$

$μ = 1.2 c m$