You visited us 1 times! Enjoying our articles? Unlock Full Access!

Frequency

An air bubble...

Question

An air bubble of radius $1 m m$ moves up with uniform velocity of $0.109 m s^{- 1}$ in a liquid column of density $14.7 \times 10^{3} k g / m^{3}$ , then coefficient of viscosity will be ( $g = 10 m s^{- 2}$ )

1.3 P a - s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

300 P a - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15 P a - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

150 P a - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1.3 P a - s$
If the bubble is moving up with uniform velocity, the frictional force acting downwards is equal to the buoyant force acting upwards.
$⟹ V ρ g = 6 π η r v$
$⟹ η = \frac{V ρ g}{6 π r v}$
$= 0.3 P a . s$

Suggest Corrections

Similar questions

^{- 1}

^{3}

^{3}

^{- 2}

ρ_{a i r}

^{3}

1.0 c m

3.5 m m / s

1.75 \times 10^{3} k g / m^{3}

r = 3 m m

v = 0.7 c m / s

1.75 g / c c

10 x

x

0.8 m m

900 k g m^{- 3}

0.15 N s m^{- 2}

\times

^{- 4}

= 10 m s^{- 2}

^{- 3}

Join BYJU'S Learning Program