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Question

An air bubble of volume 15 cm3 is formed at a depth of 50 m in a lake. If the temperature of the bubble while rising remains constant then the volume of bubble at the surface will be ( g = 10ms2 and atmospheric pressure = 1.0 X 105 Pa)

A
100 cm3
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B
90 cm3
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C
80 cm2
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D
40 cm2
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Solution

The correct option is B 90 cm3
We have pressure at the depth of 50 m as ρgh=1000×10×60=6×105kg/ms2.
As the temperature remains constant, using Boyle's law we have P1V1=P2V2 or
6×105×15=1×105×V2
or
V2=90cm3

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