An air bubble rises from the bottom of a deep lake the radius of the air bubble near the surface is 'r'. Choose the appropriate radius of the air bubble.
a) r/2 at depth 30m
b) r/2 at depth 70m
c) r/3 at depth 140m
d) r/3 at depth 260m
A
a,c
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B
a,d
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C
b,c
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D
b,d
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Solution
The correct option is D b,d At a depth of h water pressure will be Ph=Pa+ρgheq(1) where ρ=1000kg/m3 g=9.81m/s2 h=depth of water bubble Pa=105Pa initially bubble is below water at h, so P1=Ph finally it rises to surface of lake so P2=Pa we assume that temperature is constant when it is rising from bottom to surface by ideal gas equation P1V1=P2V2 volume can be written as V=43πr3 where r is radius. Ph×43πr3h=Pa×43πr3s rh=(PaPh)1/3r rh=r(PhPa)1/3 by eq(1) rh=r(Pa+ρghPa)1/3 rh=r(1+0.0981h)1/3eq(2) (a) at depth 30m h = 30m put h=30 in eq(2) rh=r1.5 false (b) at depth 70m h = 70m put h=70 in eq(2) rh=r2 true (c) at depth 140m h = 140m put h=140 in eq(2) rh=r2.4 false (d) at depth 260m h = 260m put h=260 in eq(2) rh=r3 true