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Question

An air bubble rises from the bottom of a deep lake the radius of the air bubble near the surface is 'r'. Choose the appropriate radius of the air bubble.

a) r/2 at depth 30m

b) r/2 at depth 70m

c) r/3 at depth 140m

d) r/3 at depth 260m


A
a,c
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B
a,d
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C
b,c
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D
b,d
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Solution

The correct option is D b,d
At a depth of h water pressure will be
Ph=Pa+ρgh eq(1)
where
ρ=1000kg/m3
g=9.81m/s2
h=depth of water bubble
Pa=105Pa
initially bubble is below water at h, so
P1=Ph
finally it rises to surface of lake so
P2=Pa
we assume that temperature is constant when it is rising from bottom to surface
by ideal gas equation
P1V1=P2V2
volume can be written as V=43πr3
where r is radius.
Ph×43πr3h=Pa×43πr3s
rh=(PaPh)1/3r
rh=r(PhPa)1/3
by eq(1)
rh=r(Pa+ρghPa)1/3
rh=r(1+0.0981h)1/3 eq(2)
(a) at depth 30m
h = 30m
put h=30 in eq(2)
rh=r1.5
false
(b) at depth 70m
h = 70m
put h=70 in eq(2)
rh=r2
true
(c) at depth 140m
h = 140m
put h=140 in eq(2)
rh=r2.4
false
(d) at depth 260m
h = 260m
put h=260 in eq(2)
rh=r3
true

Answer is D.

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