An air capacitor of capacity C=10μF is connected to a constant voltage battery of 12 volt. Now the space between the plates is filled with a liquid of dielectric constant 5. The (additional) charge that flows now from battery to the capacitor is :
A
120μC
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B
600μC
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C
480μC
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D
24μC
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Solution
The correct option is A480μC Initial charge qi=CV=10(12)=120μC. After filled with dielectric liquid the charge q′=C′V=KCV=5(10)12=600μC The (additional) charge that flows now from battery to the capacitor =qf−qi=600−120=480μC