An air capacitor of capacity C=10μF is connected to a constant voltage battery of 12V. Now the space between the plates is filled with a liquid of dielectric constant 5. The excess charge that flows now from battery to the capacitor is
A
120μC
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B
600μC
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C
480μC
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D
240μC
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Solution
The correct option is C480μC Charge that flows from battery to capacitor =(K−1)CV =(5−1)10×12μC=480μC