An air-craft climbs at an angle of $30^{\circ}$ at a speed of 500 metres per second. How long will it take to reach a height of 15000 metres ?

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Solution

Height ascended by the air-craft =BC = 15000M

sin $30^{\circ}$ = $\frac{15000}{A C}$

i.e, $\frac{1}{2}$ = $\frac{15000}{A C}$

$∴$ AC = 2 $\times$ 15000 = 30000m.

The air craft travels 500m, in 1 second. Hence to travel 30,000m.

it takes = $\frac{30000}{500}$ = 60 second

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An air-craft climbs at an angle of 30∘ at a speed of 500 metres per second. How long will it take to reach a height of 15000 metres ?

Height ascended by the air-craft =BC = 15000M sin 30∘ = 15000AC i.e, 12 = 15000AC ∴ AC = 2 × 15000 = 30000m. The air craft travels 500m, in 1 second. Hence to travel 30,000m. it takes = 30000500 = 60 second

An air-craft climbs at an angle of $30^{\circ}$ at a speed of 500 metres per second. How long will it take to reach a height of 15000 metres ?

Height ascended by the air-craft =BC = 15000M

sin $30^{\circ}$ = $\frac{15000}{A C}$

i.e, $\frac{1}{2}$ = $\frac{15000}{A C}$

$∴$ AC = 2 $\times$ 15000 = 30000m.

The air craft travels 500m, in 1 second. Hence to travel 30,000m.

it takes = $\frac{30000}{500}$ = 60 second