Question

An air-solenoid has 500 turns of wire in its 40 length. If the current in the wire be 1.0 A, find magnetic field at the axis inside the solenoid.

Answer 1

Formula,

$B=\frac{{\mu }_{0}NI}{l}$

$B=\frac{4\pi \times {10}^{-7}\times 500\times 1}{0.4}$

$\therefore B=1.57mT$