An air tight container having a lid with negligible mass and an area of 8 cm2 is partially evacuated. If a 48N force is required to pull the lid off the container and the atmospheric pressure is 1.0 x 105Pa, the pressure in the container before it is opened must be:
The correct option is C. 0.4atm.
The pressure required to pull the lid off the container is given by,
P′=FA=480.0008=0.6×105Pa=0.6 atm.
Therefore, pressure inside vessel P=Pair−P′
P=1−0.6
P=0.4 atm.