An aircraft executes a horizontal circular loop of radius $2 k m$ with a speed of $900 k m / h r$ . The centripetal acceleration is $x$ times the acceleration due to gravity. What is the value of $x$ if $g = 10 m / s^{2}$ ?

6.25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.12

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 3.12
Given, speed $= 900 k m / h r = 900 \times \frac{5}{18} = 250 m / s$
Centripetal acceleration of aircraft, $a_{c} = \frac{v^{2}}{r} = \frac{(250)^{2}}{2000} = \frac{62500}{2000} = 31.25 m / s^{2}$
$∴ x = \frac{a_{c}}{g} = \frac{31.25}{10} = 3.12$

Suggest Corrections

Similar questions

Q. An aircraft executes a horizontal circular loop of radius

2 k m

with a speed of

900 k m / h r

. The centripetal acceleration is

x

times the acceleration due to gravity. What is the value of

x

g = 10 m / s^{2}

An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration with the acceleration due to gravity.

Q. An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration due to gravity.

Q. An aircraft executes an horizontal loop of radius 1 km with a steady sped of 900 km/hr . Calculate the centripetal acceleration

Q. An aircraft executes a horizontal loop of radius

1 km

with a steady speed of

900 {kmh}^{- 1}

. Find its centripetal acceleration.

Join BYJU'S Learning Program

An aircraft executes a horizontal circular loop of radius 2 km with a speed of 900 km/hr. The centripetal acceleration is x times the acceleration due to gravity. What is the value of x if g=10 m/s2?

The correct option is B 3.12Given, speed =900 km/hr=900×518=250 m/s Centripetal acceleration of aircraft, ac=v2r=(250)22000=625002000=31.25 m/s2 ∴x=acg=31.2510=3.12

An aircraft executes a horizontal circular loop of radius $2 k m$ with a speed of $900 k m / h r$ . The centripetal acceleration is $x$ times the acceleration due to gravity. What is the value of $x$ if $g = 10 m / s^{2}$ ?

The correct option is B 3.12
Given, speed $= 900 k m / h r = 900 \times \frac{5}{18} = 250 m / s$
Centripetal acceleration of aircraft, $a_{c} = \frac{v^{2}}{r} = \frac{(250)^{2}}{2000} = \frac{62500}{2000} = 31.25 m / s^{2}$
$∴ x = \frac{a_{c}}{g} = \frac{31.25}{10} = 3.12$