An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15°. What is the radius of the loop ?

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Solution

Given, the horizontal loop speed of the aircraft is 720 km/h , and the angle at which the wings are banked is 15°.

The equation to determine the angle of tilt of the aircraft is,

tanθ= v 2 rg

Here, θ is the angle of tilt of the aircraft, r is the radius of the loop, v is the loop speed and g is the acceleration due to gravity.

Substitute the values in the above equation.

r= ( ( 720 km/h )( 1 h 3600 s ) ) 2 ( ( 10 m )( 1 km 1000 m ) )tan( 15° ) ≈15 km

Thus, the radius of the loop is 15 km.

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