An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration with the acceleration due to gravity.
Given: An aircraft executes a horizontal loop of radius 1.00 km and its speed is 900 kmh -1 .
Centripetal acceleration is given as,
a e = v 2 r
Where, v is the speed of the aircraft and r is the radius of loop.
By substituting the given values in the above expression, we get
a e = 900 2 1 = 8100 kmh − 2 = 62.5 ms − 2
Comparing the centripetal acceleration with the acceleration due to gravity, we get
a e g = 62.5 9.8 = 6.38 a e = 6.38 g
Thus, the magnitude of centripetal acceleration is 6.38 times the magnitude of acceleration due to gravity.
Given: An aircraft executes a horizontal loop of radius
Centripetal acceleration is given as,
Where,
By substituting the given values in the above expression, we get
Comparing the centripetal acceleration with the acceleration due to gravity, we get
Thus, the magnitude of centripetal acceleration is
