An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration due to gravity.

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Solution

Given : $r = 1000 m$ $v = 900 k m / h = 900 \times \frac{5}{18} = 250 m / s$
Centripetal acceleration $a_{c} = \frac{v^{2}}{r}$
$⟹ a_{c} = \frac{250^{2}}{1000} = 62.5 m / s^{2}$
So $\frac{a_{c}}{g} = \frac{62.5}{10} = 6.25$

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An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h. Compare its centripetal acceleration due to gravity.

Given : r=1000 m v=900 km/h=900×518=250 m/sCentripetal acceleration ac=v2r⟹ ac=25021000=62.5 m/s2So acg=62.510=6.25

Given : $r = 1000 m$ $v = 900 k m / h = 900 \times \frac{5}{18} = 250 m / s$
Centripetal acceleration $a_{c} = \frac{v^{2}}{r}$
$⟹ a_{c} = \frac{250^{2}}{1000} = 62.5 m / s^{2}$
So $\frac{a_{c}}{g} = \frac{62.5}{10} = 6.25$