An aircraft executes a horizontal loop with a speed of 150 m - s with its- wings banked at an angle of 120- The radius of the loop is g -10 m - s 2A- 10-6 kmB- 9-6 kmC- 7-4 kmD- 5-8 km

The correct option is A 10.6 km The angle of banking, tan θ = v^2/rg ⇒ tan 12^∘= (150)^2/r × 10⇒ r = 10.6 × 10^3 m=10.6km ...

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Standard XII

Physics

Banking Angle

An aircraft e...

Question

An aircraft executes a horizontal loop with a speed of 150 m/s with its, wings banked at an angle of $120^{\circ}$ . The radius of the loop is $(g = 10 m / s^{2})$

10.6 km

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9.6 km

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7.4 km

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5.8 km

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Solution

The correct option is A
10.6 km

The angle of banking, $t a n θ = \frac{v^{2}}{r g}$
$\Rightarrow t a n 12^{\circ} = \frac{(150)^{2}}{r \times 10} \Rightarrow r = 10.6 \times 10^{3} m = 10.6 k m$

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An aircraft executes a horizontal loop with a speed of 150 m/s with its, wings banked at an angle of 120∘. The radius of the loop is (g=10 m/s2)

The correct option is A 10.6 km The angle of banking, tan θ=v2rg ⇒ tan 12∘=(150)2r×10⇒r=10.6×103m=10.6km

An aircraft executes a horizontal loop with a speed of 150 m/s with its, wings banked at an angle of $120^{\circ}$ . The radius of the loop is $(g = 10 m / s^{2})$

The correct option is A
10.6 km

The angle of banking, $t a n θ = \frac{v^{2}}{r g}$
$\Rightarrow t a n 12^{\circ} = \frac{(150)^{2}}{r \times 10} \Rightarrow r = 10.6 \times 10^{3} m = 10.6 k m$