An aircraft having a wingspan of $20.48 m$ flies due north at a speed of $40 {m s}^{- 1}$ . If the vertical component of earth's magnetic field at the place is $2 \times 10^{- 5} T$ , calculate the emf induced between the ends of the wings.

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Solution

Given data:
$I = 20.48 m$ ; $V = 40 {m s}^{- 1}$ ; $B = 2 \times 10^{- 5} T$ ; $e =$ ?
Solution:
$e = - B l V$
$= - 2 \times 10^{- 5} \times 20.48 \times 40$
$e = - 0.0164$ Volt.

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An aircraft having a wingspan of 20.48m flies due north at a speed of 40ms−1. If the vertical component of earth's magnetic field at the place is 2×10−5T, calculate the emf induced between the ends of the wings.

Given data:I=20.48m; V=40ms−1; B=2×10−5T; e=?Solution:e=−BlV =−2×10−5×20.48×40e=−0.0164Volt.

An aircraft having a wingspan of $20.48 m$ flies due north at a speed of $40 {m s}^{- 1}$ . If the vertical component of earth's magnetic field at the place is $2 \times 10^{- 5} T$ , calculate the emf induced between the ends of the wings.

Given data:
$I = 20.48 m$ ; $V = 40 {m s}^{- 1}$ ; $B = 2 \times 10^{- 5} T$ ; $e =$ ?
Solution:
$e = - B l V$
$= - 2 \times 10^{- 5} \times 20.48 \times 40$
$e = - 0.0164$ Volt.