An aircraft travelling at 600 $k m h$ accelerates steadily at 10 km/h per second. Taking the speed of sound as 1100 km/h at the aircraft's altitude, how long will it take to reach the 'sound barrier'?

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Solution

Here,
Initial velocity (u) = 600 km/hr = 166.66 m/sec
Final Velocity (v) = 1100 km /hr = 305.55 m/sec
Acceleration (a) = 2.78 m/sec²
Time (t) = ?
_____________________________________________________________
By using first equation of motion,
v = u+at
a = $fraction numerator v minus u over denominator t end fraction$

t = $\frac{v - u}{a}$
$fraction numerator 305.55 minus 166.66 over denominator 2.78 end fraction t equals fraction numerator 138.89 over denominator 2.78 end fraction t equals 49.96 s e c$

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An aircraft travelling at 600 kmh accelerates steadily at 10 km/h per second. Taking the speed of sound as 1100 km/h at the aircraft's altitude, how long will it take to reach the 'sound barrier'?

Here, Initial velocity (u) = 600 km/hr = 166.66 m/sec Final Velocity (v) = 1100 km /hr = 305.55 m/sec Acceleration (a) = 2.78 m/sec² Time (t) = ? _____________________________________________________________ By using first equation of motion, v = u+at a = t = v−ua

An aircraft travelling at 600 $k m h$ accelerates steadily at 10 km/h per second. Taking the speed of sound as 1100 km/h at the aircraft's altitude, how long will it take to reach the 'sound barrier'?